-1.2x^2+x+25=0

Solution for -1.2x^2+x+25=0 equation:

-1.2x^2+x+25=0

a = -1.2; b = 1; c = +25;
Δ = b2-4ac
Δ = 12-4·(-1.2)·25
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-11}{2*-1.2}=\frac{-12}{-2.4}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+11}{2*-1.2}=\frac{10}{-2.4}
=-4+0.4/2.4
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